Question : At what point does the line $2x–3y = 6$ cuts the Y-axis?
Option 1: (0, 2)
Option 2: (–2, 0)
Option 3: (2, 0)
Option 4: (0, –2)
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Correct Answer: (0, –2)
Solution : Given: The equation is $2x–3y = 6$ The Y-axis can be expressed as $x = 0$. So, both lines should be satisfied at the intersection. Substitute $x=0$ in the equation, $2x–3y = 6$, we get, $(2×0)–3y = 6$ ⇒ $y = –2$ The point is (0, –2) which satisfies both the lines. Hence, the correct answer is (0, –2).
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Question : At what point does the line $3x+y=-6$ intercept the x-axis?
Option 1: (2, 0)
Option 3: (0, –6)
Option 4: (0, 6)
Question : Find the coordinates of the points where the graph $57x – 19y = 399$ cuts the coordinate axes.
Option 1: x-axis at(–7, 0) and y-axis at (0, –21)
Option 2: x-axis at(–7, 0) and y-axis at (0, 21)
Option 3: x-axis at (7, 0) and y-axis at (0, –21)
Option 4: x-axis at (7, 0) and y-axis at (0, 21)
Question : What is the equation of the line perpendicular to the line $2x+3y=-6$ and having y-intercept 3?
Option 1: $3x-2y=6$
Option 2: $3x-2y=-6$
Option 3: $2x-3y=-6$
Option 4: $2x-3y=6$
Question : What is the solution of the following equations? 2x + 3y = 12 and 3x – 2y = 5
Option 1: x = 3, y = 2
Option 2: x = 2, y = 3
Option 3: x = –2, y = 3
Option 4: x = 3, y = –2
Question : The graphs of the equations $4 x+\frac{1}{3} y=\frac{8}{3}$ and $\frac{1}{2} x+\frac{3}{4} y+\frac{5}{2}=0$ intersect at a point P. The point P also lies on the graph of the equation:
Option 1: $x + 2y - 5 = 0$
Option 2: $3x - y - 7 = 0$
Option 3: $x - 3y - 12= 0$
Option 4: $4x - y + 7= 0$
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