Hello there!

Here is the solution regarding your question.

Given,

T = 27°C [which is equal to 300 K].

Work done = 2.303 RT log Vf / Vi  [ for isothermal process ].

W = 2.303 x 8.31 x 300 x log 3/1 [ log 3 = 0.48 ].

W = 19.1 x 300 x 0.48

W = 19.1 x 144

W = 2750.4 Joule

W = 2.75 x 10³ Joule.

Hence, the work done is 2.75 x 10³ Joule.

Hope you got your answer.