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can a 4rth year student can apply for the csir jrf exam


naveen Kumar 29th Jan, 2020
Answers (2)
Muskan 29th Jan, 2020

Hi Naveen

Eligibility criteria for CSIR exam are :

Candidates must have a degree in B.Pharma ( Bachelor in Pharmacy ) or BE ( Bachelor in Engineering ) or MSC (Masters in respective course ) or MBBS or BS - MS with atleast 55 % marks .

Aspirants who are currently pursuing MSc and have completed graduation are also eligible to apply.

Candidate who have done BSc or if they are pursuing the integrated MSc - PhD program are also eligible.

Candidates who have completed graduation from science or engineering background can also get the fellowship , provided they register for PhD or PhD integrated program within two years.

Since you did not specify your course so i provided you with the overall eligibility criteria for csir exam.

For further information you can refer to the  link below : https://competition.careers360.com/articles/csir-ugc-net-2019

All the best !!

Hope it helps :)


1 Comment
Comments (1)
29th Jan, 2020
But im in 8th sem persuing mechanical engineering am i eligible for csir jrf exam in 2020
Reply
Atulya Himanshu 29th Jan, 2020

Hi,

Yes, you are eligible to apply for the CSIR UGC NET exam

CSIR NET Eligibility 2020 is stipulated by the NTA (National Testing Agency). Candidates willing to apply for CSIR UGC NET 2020 (https://collegedunia.com/exams/csir-ugc-net) must possess M.Sc. or equivalent degree/Integrated BS-MS/BS-4 years/BE/B Tech/B. Pharma /MBBS with at least 55% marks to be eligible to apply for the exam. CSIR NET Exam will be held on June 21, 2020.


Before applying for CSIR NET, candidates should go through the eligibility requirements for CSIR NET. If any candidate is found to be ineligible at later stages then the candidature would be rejected straightaway.


Hope this helps! All The Best!!


Feel free to ask if you have any more queries

1 Comment
Comments (1)
29th Jan, 2020
But im in 8th sem persuing mechanical engineering am i eligible for csir jrf exam in 2020
Reply

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