The cutoff for NITs (National Institutes of Technology) for the General category is determined by your JEE Main percentile and rank.
Qualifying Percentile (to be eligible for NITs):
General category: You need at least 93.10 percentile to qualify for JEE Advanced, but for NIT admission, the cutoff is usually higher (https://www.aakash.ac.in/jee-main-cut-off) .
Expected safe percentile for NIT admission: 95+ percentile (https://www.shiksha.com/engineering/articles/nit-cutoff-blogId-20217) (https://testbook.com/jee-main/cutoff) .
Expected Cutoff Marks:
For General category, the cutoff is typically between 92 and 100 marks in JEE Main 2025 5 (https://testbook.com/jee-main/cutoff) .
Rank-wise Cutoff for Top Branches (e.g., CSE):
For top NITs and popular branches like Computer Science, closing ranks for General category are often below 10,000 (sometimes even lower for the most in-demand NITs) (https://www.shiksha.com/engineering/jee-main-exam-cutoff) .
For other branches and lower-tier NITs, closing ranks can go up to 200,000–300,000 .
Higher percentile and lower rank are needed for top NITs and branches like CSE.
Cutoff changes every year based on difficulty, number of applicants, and seat availability.
JoSAA counseling releases round-wise opening and closing ranks for each NIT and branch after the JEE Main results. (https://www.shiksha.com/engineering/articles/nit-cutoff-blogId-20217)
In short:
For NIT admission in the General category, aim for at least 95+ percentile or 92–100 marks in JEE Main 2025.
For top branches (like CSE), you’ll need a much better rank (often under 10,000).
Check JoSAA counseling rounds for precise, branch-wise, and NIT-wise cutoffs after results are published.
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