Hello there

De Broglie wavelength is given by the formula

Lamda=h/sqaurerootof (2×m×e×V) where m is the mass of an electron,e the charge and V is the potential difference.When a 50V is applied the the wavelength is 1.73×10^-10m

Hope I was able to help you out.

Hello Dakshi,

Your question is assosciated with modern physics chapter. The solution is given as follows:

Answer for your question is is 1.7A.

For on electron , de-Broglie wavelength is given by ,

λ=sqrt(150/V)=sqrt(150/50)=

1.73A

A=armstrong, 1A=10^(-10)m

Hope this Helps

Regards