Question : DEF is an isosceles triangle such that DE = DF = 60 cm and EF = 96 cm. DG is a median to base EF. What is the length of DG?
Option 1: 22 cm
Option 2: 36 cm
Option 3: 24 cm
Option 4: 32 cm
Correct Answer: 36 cm
Solution : Given: DE = DF = 60 cm, EF = 96 DG median cuts EF into two halves. So, EG = $\frac{96}{2}=48$ cm In $\triangle$DEG, DE2 = DG2 + EG2 ⇒ DG = $\sqrt{60^2-48^2}=\sqrt{1296}=36$ cm Hence, the correct answer is 36 cm.
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Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are two triangles such that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$. If AB = 5 cm, $\angle$B = 40° and $\angle$A = 80°, then which of the following options is true?
Option 1: DF = 5 cm, $\angle$E = 60°
Option 2: DE = 5 cm, $\angle$F = 60°
Option 3: DE = 5 cm, $\angle$D = 60°
Option 4: DE = 5 cm, $\angle$E = 60°
Question : If $\triangle$DEF is right-angled at E, DE = 15, and $\angle$DFE = 60° then, what is the value of EF?
Option 1: $5\sqrt3$
Option 2: $5$
Option 3: $15$
Option 4: $30$
Question : A sector of a circle has a central angle of 45° and an arc length of 22 cm. Find the radius of the circle. ( Use $\pi=\frac{22}{7}$)
Option 1: 32 cm
Option 2: 35 cm
Option 3: 28 cm
Option 4: 36 cm
Question : ABC is an equilateral triangle points D, E and F are taken in sides AB, BC and CA respectively so that, AD = BE = CF. Then DE, EF, and FD enclose a triangle which is:
Option 1: equilateral
Option 2: isosceles
Option 3: right angled
Option 4: none
Question : In a triangle ABC, $\angle$BAC = 90°. If BC = 25 cm, then what is the length of the median AD?
Option 1: 10 cm
Option 2: 12.5 cm
Option 3: 14.5 cm
Option 4: 24 cm
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