Question : If $\triangle$DEF is right-angled at E, DE = 15, and $\angle$DFE = 60° then, what is the value of EF?
Option 1: $5\sqrt3$
Option 2: $5$
Option 3: $15$
Option 4: $30$
Correct Answer: $5\sqrt3$
 
  Solution :
 
 
 
  Given: DE = 15 and $\angle$DFE = 60°
  
  We know, $\tan\theta$ = $\frac{\text{Perpendicular}}{\text{Base}}$
  
  ⇒ $\tan 60° = \frac{DE}{EF} = \sqrt{3}$
  
  ⇒ EF = $\frac{DE}{\sqrt{3}}$
  
  ⇒ EF = $\frac{15}{\sqrt{3}}$
  
  $\therefore$ EF = $5\sqrt{3}$
  
  Hence, the correct answer is $5\sqrt{3}$.
 
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