Hello,

Let the volume of the solution is  1 L or 1000 ml

Now, 1 ml = 1.2 gm, therefore 1000 ml = 1000 * 1.2 = 1200 gm

Number of moles in 1 L of solution = 2.05 moles

Mass of solute = nunmber of moles * molecular weight

= 2.05 * 60 = 123 gm

Solvent mass = 1020 - 123 = 897 gm

Now we know that Molality = moles of solute/kg of solvent

Molality = 123/60 * 1000/897

Solving the above equation, we get:

Molality = 2.28 mol/kg (Answer)