3267 Views
Density remaining constant if earth contracts to half of its present radius duration of the day would be in minutes
Answer (1)
Using conservation of angular momentum
2/5 mR²w= const.
I(w), wR², 2πfR², R²/T =const.
so, T is directly proportional to square of radius
Now if radius is decreased to half then,
T'= T/4
therefore which is 24/4
which implies that the time period will be 6 hours.
Related Questions
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Great Lakes PGPM & PGDM Admis...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024