Question : Directions: A was twice as old as B, two years ago. If the difference in their ages is 2 years, find A's age.
Option 1: 6 years
Option 2: 8 years
Option 3: 10 years
Option 4: 4 years

Let, the present age of A = A years, and the present age of B = B years
As per the given information, A = (B + 2)
Two years ago, A's age = (A – 2) years, and B's age = (B – 2) years.
⇒ (A – 2) = 2 × (B – 2)
⇒ A – 2 = 2B – 4
⇒ 4 – 2 = 2B – A
⇒ 2B – A = 2
Now, substitute the value of A = B + 2 in the above equation,
⇒ 2B – (B + 2) = 2
⇒ 2B – B – 2 = 2
⇒ B = 2 + 2 ⇒ B = 4 years