Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: AJDG
Option 2: KTNQ
Option 3: JMSP
Option 4: UDXA
Correct Answer: JMSP
Solution : Let's check the options – First option: AJDG; A + 9 = J; J – 6 = D; D + 3 = G Second option: KTNQ; K + 9 = T; T – 6 = N; N + 3 = Q Third option: JMSP; J + 3 = M; M + 6 = S; S – 3 = P Fourth option: UDXA; U + 9 = D; D – 6 = X; X + 3 = A
So, the third option is different from the other three options because the difference in the position value of the letters is different. Hence, the third option is correct.
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Option 1: CX
Option 2: EV
Option 3: JR
Option 4: LO
Option 1: UVX
Option 2: BCD
Option 3: HIJ
Option 4: PQR
Option 1: OMNLM
Option 2: TOQOP
Option 3: WUVTU
Option 4: RPQOP
Option 1: KMO
Option 2: UXA
Option 3: CEG
Option 4: LNP
Option 1: NPLRJ
Option 2: TVRXQ
Option 3: FHDJB
Option 4: WYUAS
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