Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: OMNLM
Option 2: TOQOP
Option 3: WUVTU
Option 4: RPQOP
Correct Answer: TOQOP
Solution : Let's check the options – First option: OMNLM; O – 2 = M; M + 1 = N; N – 2 = L; L + 1 = M Second option: TOQOP; T – 5 = O; O + 2 = Q; Q – 2 = O; O + 1 = P Third option: WUVTU; W – 2 = U; U + 1 = V; V – 2 = T; T + 1 = U Fourth option: RPQOP; R – 2 = P; P + 1 = Q; Q – 2 = O; O + 1 = P
So, the second option is different from the other three options because the difference in the position value of the letters is different. Hence, the second option is correct.
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Option 1: AJDG
Option 2: KTNQ
Option 3: JMSP
Option 4: UDXA
Option 1: CX
Option 2: EV
Option 3: JR
Option 4: LO
Option 1: UVX
Option 2: BCD
Option 3: HIJ
Option 4: PQR
Option 1: KMO
Option 2: UXA
Option 3: CEG
Option 4: LNP
Option 1: NPLRJ
Option 2: TVRXQ
Option 3: FHDJB
Option 4: WYUAS
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