Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: AG
Option 2: WA
Option 3: ET
Option 4: IQ
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Correct Answer: ET
Solution : Let's check the options – First option: AG; A (1) + G (7) = 7 + 1 = 8 (This is an even number.) Second option: WA; W (23) + A (1) = 23 + 1 = 24 (This is an even number.) Third option: ET; E (5) + T (20) = 20 + 5 = 25 (This is an odd number.) Fourth option: IQ; I (9) + Q (17) = 9 + 17 = 26 (This is an even number.)
So, the third option is different from the other options as the resultant is an odd number. Hence, the third option is correct.
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Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
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Option 2: JLOS
Option 3: NPSW
Option 4: MORU
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Option 2: FD
Option 3: KI
Option 4: TQ
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Option 2: BDCB
Option 3: XZYX
Option 4: PRQP
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Option 4: JOP
Option 1: OMQ
Option 2: TPR
Option 3: TRV
Option 4: VTX
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