Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: CBED
Option 2: JILK
Option 3: TSVU
Option 4: VZXY
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Correct Answer: VZXY
Solution : Let's check the options – First option: CBED; C – 1 = B; B + 3 = E; E – 1 = D Second option: JILK; J – 1 = I; I + 3 = L; L – 1 = K Third option: TSVU; T – 1 = S; S + 3 = V; V – 1 = U Fourth option: VZXY; V + 4 = Z; Z – 2 = X; X + 1 = Y
So, the fourth option is different from the other three options because the difference in the position value of the letters is different. Hence, the fourth option is correct.
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Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Option 1: BDGK
Option 2: JLOS
Option 3: NPSW
Option 4: MORU
Option 1: CA
Option 2: FD
Option 3: KI
Option 4: TQ
Option 1: MNOM
Option 2: BDCB
Option 3: XZYX
Option 4: PRQP
Option 1: TOP
Option 2: COP
Option 3: MOP
Option 4: JOP
Option 1: OMQ
Option 2: TPR
Option 3: TRV
Option 4: VTX
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