Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: SU
Option 2: BD
Option 3: IK
Option 4: PN
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Correct Answer: PN
Solution : Let's check the options –
First option: SU; S + 2 = U Second option: BD; B + 2 = D Third option: IK; I + 2 = K Fourth option: PN; P – 2 = N
So, the fourth option is different from the other three options because the difference in the position value of the letters is –2 instead of +2. Hence, the fourth option is correct.
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Option 1: BD
Option 2: CD
Option 3: DF
Option 4: AC
Option 1: CGFJ
Option 2: EIHL
Option 3: GKIN
Option 4: IMNR
Option 1: LNP
Option 2: MOQ
Option 3: BDE
Option 4: EGI
Option 1: YXWV
Option 2: FUEV
Option 3: QPSR
Option 4: VUXW
Option 1: NKM
Option 2: DAC
Option 3: UTV
Option 4: IFH
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