Question : Evaluate $\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}$, given that $\sqrt{6}=2.45$.
Option 1: 7.7
Option 2: 9.9
Option 3: 8.8
Option 4: 6.6
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Correct Answer: 9.9
Solution : $\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}$ Rationalizing the denominator, = $\frac{(\sqrt{3}+\sqrt{2})^2}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}$ = $\frac{(3+2+2\sqrt{6})}{(3-2)}$ = $5+2\sqrt6$ = 5 + (2 × 2.45) = 5 + 4.9 = 9.9 Hence, the correct answer is 9.9.
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Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:
Option 1: $\frac{2 \sqrt{6}-6}{5}$
Option 2: $\frac{4 \sqrt{6}-6}{5}$
Option 3: $\frac{4 \sqrt{6}-6}{3}$
Option 4: $\frac{4 \sqrt{3}-6}{5}$
Question : The simplified value of $\frac{3\sqrt 2 }{\sqrt3 + \sqrt6} - \frac{4 \sqrt 3 }{\sqrt{6}+ \sqrt {2}} + \frac{\sqrt 6}{\sqrt{3}+ \sqrt 2}$ is:
Option 1: $\sqrt 2$
Option 2: $\frac{1}{\sqrt2}$
Option 3: $\sqrt 3- \sqrt 2$
Option 4: $0$
Question : The value of exponential form of $\sqrt{\sqrt{2}\sqrt{3}}$ is:
Option 1: $6$
Option 2: $6^{\frac{1}{2}}$
Option 3: $6^{-\frac{1}{2}}$
Option 4: $6^{\frac{1}{4}}$
Question : Evaluate $\sqrt{20}+\sqrt{12}+\sqrt[3]{729}-\frac{4}{\sqrt{5}-\sqrt{3}}-\sqrt{81}:$
Option 1: $\sqrt{2}$
Option 2: $\sqrt{3}$
Option 3: $0$
Option 4: $2\sqrt{2}$
Question : The value of $\frac{1}{1+\sqrt{2}+\sqrt{3}}+\frac{1}{1-\sqrt{2}+\sqrt{3}}$ is:
Option 3: $1$
Option 4: $4(\sqrt{3}+\sqrt{2})$
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