Dear aspirant,
You can solve this pretty normally by binomial expansion , so the value of n here is 3 so go by the formula:-
Take 2x as 1st and 2-y as second group
nC0 (2x)^3 (2-y)^0+ nC1(2x)^2 (2-y)^1+ nC2 (2x)^1(2-y)^2 + nC3 (2x)^0 (2-y)^3.
Just evaluate this equation ,you will get your desired result.
Question : The algebraic expression $4x^2-y^2+6y-9$ is equal to______.
Option 1: $(2x + y - 3)(2x - y + 3)$
Option 2: $(2x - y - 3)(2x - y + 3)$
Option 3: $(2x + y - 3)^2$
Option 4: $(2x + y + 3)^2$
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