Given, vec(A) =-2i+2j-k

vec(B )= 3i+6j+2k.

Now A cross B =

| i                j              k  |

| -2             2              -1|

| 3              6               2 |

=> A cross B = i(2*2-[-1*6])-j(-2*2-[-1*3])+k(-2*6-[2*3])

=> A cross B = 10i +j - 18k

I hope this answer helps. All the very best for your future endeavors!