Hi there,

Hope you are doing well.

Choosing to study astronomy can be exciting and intellectually rewarding. However pursuing a career in astronomy generally  requires a strong foundation in physics, mathematics, and sometimes computer science.

Both the jee exam and the cet exam are for different purposes. Giving the jee

Hello,

It is very important to understand the concept of Degree of Freedom before you approach the question.

------- DOF or Degree of freedom in layman terms is basically no. Of ways in which a molecule can attain energy.

-------- So energy can be acquired by Translational motion, rotational motion

Dear Aspirant, since Y-chromosome possesses small amount of euchromatin that contains DNA or genes, therefore it is genetically less active. Recent research has shown that the Y chromosome has developed some pretty convincing mechanisms to "put the brakes on", slowing the rate of gene loss to a possible standstill. I

Hello,

You can get the detailed solution for your query proving that the cross product of two vectors is equal to the area of the parallelogram.

Here is the link for the solution-

https://learn.careers360.com/school/question-prove-that-cross-product-of-two-vectors-is-equal-to-the-area-of-a-parallelogram-43718/

Thank you.

Hello,

You can get the detailed solution for your query proving that the cross product of two vectors is equal to the area of the parallelogram.

Here is the link for the solution-

https://learn.careers360.com/school/question-prove-that-cross-product-of-two-vectors-is-equal-to-the-area-of-a-parallelogram-43718/

Thank you.

Dear Aspirant,

the repeated questions for NEET examinations are generally in most cases low, as the level of competition is very high. In most cases similar kinds of questions are asked instead of repeating the same question. However, there are a few times where a question or two are repeated

Hey,

In order to find the magnitude of a vector the formula is,

R^2= P^2 + Q^2 + 2 PQ cos¢

Now given, R= P+ Q

Squaring both sides,  R^2= P^2 + Q^2 + 2PQ

Equating both the reaction,

R^2= P^2 + Q^2 + 2 PQ cos¢   = R^2= P^2