CO2} is linear triatomic molecule. The average K.E. at temperature T will be: D) 7KT / 2 C) 6kT / 2 B) 5kT / 2 A) 3kT / 2 what will be the ans.?? is A is the ans??? pls justify..
Hello,
It is very important to understand the concept of Degree of Freedom before you approach the question.
------- DOF or Degree of freedom in layman terms is basically no. Of ways in which a molecule can attain energy.
-------- So energy can be acquired by Translational motion, rotational motion and vibratory motion ( only at high temperatures).
-------- So, for a diatomic molecule and triatomic linear molecule like CO2 following DOF are associated with each form of motion:
• Translational motion - 3
• Rotational motion - 2
• Vibratory Motion - 2 (Only at High Temperature)
-------- Also energy associated with 1 DOF as per Maxwell's Law of equipartition of energy = 1/2KT ( K = Boltzmann Constant)
--------- Hence total Energy for CO2 molecule at normal temperature is 5/2KT.
I hope you find the answer helpful.
Thank you.
Y chromosome is less active why
Dear Aspirant, since Y-chromosome possesses small amount of euchromatin that contains DNA or genes, therefore it is genetically less active. Recent research has shown that the Y chromosome has developed some pretty convincing mechanisms to "put the brakes on", slowing the rate of gene loss to a possible standstill. I hope you are clear now. If you have any other doubts feel free to ask. All The Best!!!
Prove that cross product of two vectors is equal to the area of parallelogram
Hello,
You can get the detailed solution for your query proving that the cross product of two vectors is equal to the area of the parallelogram.
Here is the link for the solution-
Thank you.
Prove the are of parallelogram by vector
Hello,
You can get the detailed solution for your query proving that the cross product of two vectors is equal to the area of the parallelogram.
Here is the link for the solution-
Thank you.
If coefficient of friction is 0.5 , Applied force on a block is 49 N and mass of block is 10 kg then acceleration is ?
We have = 0.5
f=N
Where N = mg
= 0.51010=50N
So, net force acting on the block in horizontal direction = 50N-49 N = 1 N
So, Acceleration of the block = Net force / mass of block = 1 N/10 kg = 0.1 meter per second square.
I hope that's clear.
Assertion: The two bodies of masses M and m (M > m) are allowed to fall from the same height if the air resistance for each be the same then both the bodies will reach the earth simultaneously. Reason : For same air resistance, acceleration of both the bodies will be same What is answer ?
Answer - Both assertion and reason are false.
Two forces acting on the body of mass M are weight (Mg, where g = acceleration due to gravity) that can be seen acting vertically downwards and second one is the air resistance acting vertically upward.
Acceleration of the body
a = (Mg - F)/M
a = g - F/M
Since, M > m (Given) therefore, the body with larger mass will be accelerated more and hence it will reach the ground first.
what is difference between periodic motion and harmonic motion? N.B only harmonic motion not simple harmonic motion
Hi aspirant,
If we try to understand Periodic motion in simplest words it can be defined as the motion that repeats itself regularly at fixed intervals of time. It is path independent and time intervals may range from seconds to years. For example: a car moving on a straight road is said to have linear motion, the motion of the earth around the sun is circular motion, moving of pendulum is a harmonic motion.
Harmonic motion is just a special case of Periodic motion which is , repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side.
Note- Harmonic motion refers to simple harmonic motion only unless it's type is defined.
Hope it helps!!
how many and which questions were repeated in neet 2020?
Dear Aspirant,
the repeated questions for NEET examinations are generally in most cases low, as the level of competition is very high. In most cases similar kinds of questions are asked instead of repeating the same question. However, there are a few times where a question or two are repeated from the previous years. Hence to get to know of some of these repeated questions or similar questions that are asked through out the year in NEET, you may solve the previous years question papers. They are very beneficial as it not only gives you an idea of the similar questions but also helps you get familiar with question paper pattern.
To view the previous years question papers, kindly visit the link provided below.
https://medicine.careers360.com/articles/neet-question-paper
if R vector = P vector + Q vector and R = P +Q find angle between P vector and Q vector
Hey,
In order to find the magnitude of a vector the formula is,
R^2= P^2 + Q^2 + 2 PQ cos¢
Now given, R= P+ Q
Squaring both sides, R^2= P^2 + Q^2 + 2PQ
Equating both the reaction,
R^2= P^2 + Q^2 + 2 PQ cos¢ = R^2= P^2 + Q^2 + 2PQ
Simplifying, cos¢ = 1
= Cos 0° = 1
Therefore the angle is 0 degree.
Hope that helps.
Thank you.