595 Views

find the condition that one root of x square + bx + c equal to zero maybe n times the other root


bhukyasrikanth8978 17th Dec, 2020
Answer (1)
ARYAN SAGAR 17th Dec, 2020

Dear student,

The equation is given as :-

x^2 + bx + c = 0

Now, it is given that one root of the equation is n times the other root. So, let one of the root be k.

So, the other root will become nk.

Now sum of root = - coefficient of x / coefficient of x^2

Product of roots is = constant term / (coefficient of x^2)

Now,

Sum of root = nk+k = k(1+n) = -b /1

And product of root = (nk)k = nk^2 = c /1

From equation 1st, we have :-

k = -b/(1+n)

Substituting the value of k in equation 2nd we get :-

{(1+n)^2} / n = (b^2) / c

So, we got our final condition, if one of the root is n times the other.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
VIT - VITEEE 2026
Apply
National level exam conducted by VIT University, Vellore | Ranked #16 by NIRF for Engg. | NAAC A++ Accredited
RV University, Bangalore | La...
Apply
Excellent curriculum; an impressive range of electives, besides core law courses. Up to 100% merit scholarship on a first-come, first-served basis
Amity University-Noida M.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida MBA Ad...
Apply
Ranked among top 10 B-Schools in India by multiple publications | Top Recruiters-Google, MicKinsey, Amazon, BCG & many more.
Great Lakes Institute of Mana...
Apply
Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books