The distance AB = $((1-0)^2 + (0-0)^2 + (2-0)^2)^(1/2)$
AB = $(5)^(1/2)$
Question : If the phase difference between two points is 1200 for a wave with a velocity of 360 m/s and a frequency of 500 Hz, then the path difference between the two points is:
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