Distance between points(asin60,0) and (0,acos60) is
Answer (1)
23rd Feb, 2021
Hello Candidate,
the distance between any two arbitrary points in a two dimensional plane is given by the square root of the difference modulus of x square components and y square components and adding them both.
So, in the given question the distance between the two points is equal to- √{asin60-0}^2+ {acos60-0}^2}= √a^2 sin^2(60)+ a^2 cos^(60)= a.
Hope that this Answer helps you!!
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