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A general equation of a circle is
$ x^2+y^2+2 g x+2 f y+c=0 $
Since it passes through $(0,0)$,
$ c=0 $
So the equation becomes
$ x^2+y^2+2 g x+2 f y=0 $
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$ a^2+2 g a=0 $
g=-a/2
It cuts the y -axis at $(0, b)$.
$ b^2+2 f b=0 \Rightarrow f=-\frac{b}{2} $
Putting values of $g$ and $f$ :
$ x^2+y^2-a x-b y=0 $
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Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer. Due to heavy rains, the match was called____.
Option 1: of
Option 2: off
Option 3: down
Option 4: out
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