Question : Find the greatest number that will divide 390, 495, and 300 without leaving a remainder.
Option 1: 5
Option 2: 15
Option 3: 25
Option 4: 35
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Correct Answer: 15
Solution : HCF of the given numbers: 390 = (2 × 3 × 5 × 13) 495 = (3× 3 × 5 × 11) 300 = (2 × 2 × 3 × 5 × 5) Now HCF = (3 × 5) = 15 So, 15 is the number that can divide 390, 495, and 300 without leaving a remainder. Hence, the correct answer is 15.
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Question : Find the greatest number that will divide 49, 147, and 322 to leave the same remainder in each case.
Option 1: 9
Option 2: 5
Option 3: 7
Option 4: 8
Question : Find the remainder when we divide $3x^4-2x^2+4x-1$ by $(2x-1)$.
Option 1: $2$
Option 2: $3$
Option 3: $\frac{11}{16}$
Option 4: $\frac{15}{16}$
Question : When a number is divided by 45, the remainder is 21. What will be the remainder when the number is divided by 15?
Option 1: 6
Option 3: 3
Option 4: 0
Question : A number $n$ when divided by 6, leaves a remainder of 3. What will be the remainder when $\left(n^2+5 n+8\right)$ is divided by 6?
Option 1: 1
Option 2: 3
Option 3: 5
Option 4: 2
Question : Find the greatest number which will exactly divide 200 and 320.
Option 1: 10
Option 2: 20
Option 3: 16
Option 4: 40
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