Question : Find the mean proportion of $x^3y$ and $xy^3$.
Option 1: $x^2y^2$
Option 2: $x^3y^3$
Option 3: $xy$
Option 4: $x^4 y^4$
Correct Answer: $x^2y^2$
Solution : Let the mean proportion be $a$ Given numbers, $x^3y$ and $xy^3$ ⇒ $a^2=x^3y\times xy^3$ ⇒ $a^2=x^4y^4$ ⇒ $a=x^2y^2$ Hence, the correct answer is $x^2y^2$.
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Question : Simplify the given expression. $(x - 2y)(y - 3x) + (x + y)(x - y) + (x - 3y)(2x + y)$
Option 1: $2y(x - 3y)$
Option 2: $2y(x + 3y)$
Option 3: $2x(x - 3y)$
Option 4: $2x(x + 3y)$
Question : If $x^4+x^2 y^2+y^4=133$ and $x^2-x y+y^2=7$, then what is the value of $xy$?
Option 1: 8
Option 2: 12
Option 3: 4
Option 4: 6
Question : If $x= 19$ and $y= 18$, then the value of $\frac{x^{2}+y^{2}+xy}{x^{3}-y^{3}}$ is:
Option 1: 1
Option 2: 37
Option 3: 324
Option 4: 361
Question : If $x^4+x^2 y^2+y^4=21$ and $x^2+xy+y^2=3$, then what is the value of $4xy $?
Option 1: –8
Option 2: 4
Option 3: –4
Option 4: 12
Question : What is the simplified value of: $\frac{1}{8}\left\{\left(x+\frac{1}{y}\right)^2-\left(x-\frac{1}{y}\right)^2\right\}$
Option 1: $\frac{x}{y}$
Option 2: $\frac{2x}{y}$
Option 3: $\frac{x}{2y}$
Option 4: $\frac{4x}{y}$
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