Question : Find the numerical value of $\frac{9}{\operatorname{cosec^{2}\theta}}+4\cos^{2}\theta+\frac{5}{1+\tan^{2}\theta}$
Option 1: $5$
Option 2: $7$
Option 3: $9$
Option 4: $4$
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Correct Answer: $9$
Solution : Given: $\frac{9}{\operatorname{cosec^{2}\theta}}+4\cos^{2}\theta+\frac{5}{1+\tan^{2}\theta}$ $=9\sin^2\theta+4\cos^{2}\theta+\frac{5}{\operatorname{sec^{2}\theta}}$ $=9\sin^2\theta+4\cos^{2}\theta+5\cos^{2}\theta$ $=9\sin^2\theta+9\cos^{2}\theta$ $=9(\sin^2\theta+\cos^{2}\theta)$ $=9$ [$\because \sin^2\theta+\cos^{2}\theta=1$] Hence, the correct answer is $9$.
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Question : If $\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}=\frac{4}{5}$, then the value of $\frac{\operatorname{cosec}^2 \theta}{2-\operatorname{cosec}^2 \theta}$ is:
Option 1: $\frac{16}{25}$
Option 2: $\frac{40}{41}$
Option 3: $\frac{41}{40}$
Option 4: $\frac{31}{30}$
Question : If $6 \sec \theta=10$, then find the value of $\frac{5 \operatorname{cosec} \theta-3 \cot \theta}{4 \cos \theta+3 \sin \theta}$.
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{6}{5}$
Question : If $\sin \theta+\cos \theta=\frac{1}{29}$, then find the value of $\frac{\operatorname{sin} \theta+\operatorname{cos} \theta}{\operatorname{sin} \theta-\operatorname{cos} \theta}$.
Option 1: $\frac{1}{41}$
Option 2: $\frac{43}{29}$
Option 3: $\frac{41}{29}$
Option 4: $\frac{1}{43}$
Question : If $\sin \theta-\cos \theta=\frac{1}{5}$, then find the value of $\sin \theta+\cos \theta$.
Option 1: $\frac{5}{7}$
Option 2: $\frac{7}{5}$
Option 3: $\frac{5}{3}$
Option 4: $\frac{3}{5}$
Question : What is the value of $\frac{\cot \theta+\operatorname{cosec} \theta-1}{\cot \theta-\operatorname{cosec} \theta+1}$?
Option 1: $2 \sec \theta$
Option 2: $2 \operatorname{cosec} \theta$
Option 3: $2 \cot \theta$
Option 4: $\operatorname{cosec} \theta+\cot \theta$
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