WWe know that x² >= 0 for all x€R
Therefore 1+x²>= 1 for all x€R
Thus the denominator is always greater than the numerator. i. e. 1+x²>x² so,
x²÷(1+x²) is always less than 1.Also, It is never equal to 1.
At x=0, the value of expression is 0.
Thus the required Range of function is [0, 1).
Hope you get it.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile