Question : Find the value of $x$ in the given figure where TP (tangent on point T) = 15 cm, PB = 2$x$ + 3 cm, PA = 9 cm.
Option 1: 21 cm
Option 2: 18 cm
Option 3: 15 cm
Option 4: 11 cm
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Correct Answer: 11 cm
Solution : TP = 15 cm PB = 2$x$ + 3 cm PA = 9 cm If a secant AB and tangent at the point T of a circle intersect at a point T of a circle intersect at a point P outside the circle, then PA × PB = PT2 9 × (2$x$ + 3) = 152 ⇒ 2$x$ + 3 = $\frac{225}{9}$ = 25 ⇒ $x$ = $\frac{25-3}{2}$ = 11 Hence, the correct answer is 11 cm.
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Question :
In the figure, PT is a tangent. If TP = 12 cm, PB = $x$ + 7 cm, and PA = $x$ cm, then find the value of $x$.
Option 1: 9
Option 2: 6
Option 3: 7
Option 4: 5
Question : In the figure, AB = AD = 9 cm, AC = AE = 13 cm, and BC = 15 cm. Find ED.
Option 1: 18 cm
Option 2: 16 cm
Option 3: 14 cm
Option 4: 15 cm
Question : In the following figure, O is the centre of the circle. Its two chords AB and CD intersect each other at point P inside the circle. If AB =18 cm, PB = 6 cm, and CP = 4 cm, then find the measure of PD.
Option 1: 14 cm
Option 3: 16 cm
Option 4: 20 cm
Question : In the given figure, PQR is a triangle, and quadrilateral ABCD is inscribed in it. QD = 2 cm, QC = 5 cm, CR = 3 cm, BR = 4 cm, PB = 6 cm, PA = 5 cm and AD = 3 cm. What is the area (in cm2) of the quadrilateral ABCD?
Option 1: $\frac{(23\sqrt{21})}{4}$
Option 2: $\frac{(15\sqrt{21})}{4}$
Option 3: $\frac{(17\sqrt{21})}{5}$
Option 4: $\frac{(23\sqrt{21})}{5}$
Question : In the given figure, the diameter AB and chord CD of a circle meet at P. PT is tangent to the circle at T. If CD = 8 cm, PD = 10 cm, and PB = 8 cm, find AB.
Option 1: 14.5 cm
Option 2: 22.5 cm
Option 3: 12 cm
Option 4: 8 cm
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