Question : Find the weight of a cylindrical iron container with a base of radius 12.6 cm and height is 4 m, where the weight of 1 cm2 of iron is 2 grams.
Option 1: 299.284 kg
Option 2: 199.584 kg
Option 3: 399.168 kg
Option 4: 499.482 kg
New: SSC MTS Tier 1 Answer key 2024 out
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 399.168 kg
Solution : The radius of the cylinder, $r$ = 12.6 cm Height, $h$ = 4 m = 400 cm Volume of a cylinder = $\pi r^2 h=\frac{22}{7}×(12.6)^2×400\ \text{cm}^2$ The weight of 1 cm2 of iron is 2 grams. Total weight of the iron = $\frac{22}{7}×(12.6)^2×400×2=399168\ \text{gram}=399.168\ \text{kg}$ Hence, the correct answer is 399.168 kg.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : Find the curved surface area of a cone whose radius of the base is 7 cm and slant height is 8 cm. [Use $\pi=\frac{22}{7}$]
Option 1: 132 cm2
Option 2: 198 cm2
Option 3: 154 cm2
Option 4: 176 cm2
Question : Find the area of the triangle whose height is 56 cm and the corresponding base is $\frac{1}{4}$th of the height.
Option 1: 544 cm2
Option 2: 440 cm2
Option 3: 392 cm2
Option 4: 480 cm2
Question : Find out the area of the triangle of base 7 cm and the corresponding height of 12 cm.
Option 1: 42 cm2
Option 2: 54 cm2
Option 3: 43 cm2
Option 4: 44 cm2
Question : What is the area of the lateral surface of a right circular cylinder, If the circumference of the base is 22 cm and its height is four times its radius?
Option 1: 388 cm2
Option 2: 308 cm2
Option 3: 408 cm2
Option 4: 288 cm2
Question : Find the surface area of a spherical ball that has a radius of 1.1 cm.
Option 1: 16 cm2
Option 2: 12.1 cm2
Option 3: 11.2 cm2
Option 4: 15.2 cm2
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile