181 Views

for the following first order ordinary differential equation dy/dt=5y-6t y(0)=-2


pasupulatimareswarao 14th May, 2020
Answer (1)
Rishi Garg 10th Jul, 2020

We are given that  dy/dt = 5y - 6t

rearranging which, we get, dy = 5y.dt - 6t.dt

Integrating both sides, we get

y = 5y.t - 3(t^2) + c

Given, y(0) = -2

which gives,

-2 = 0 + 0 +c

implies C = -2

Hence, the required equation is y = 5y.t - 3(t^2) - 2.

Hope it helps.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Narayana Business School MBA/...
Apply
Top 30 Private B-Schools Nationally and Top 3 in Gujarat | Highest CTC- 20 LPA | Average CTC- 8.4 LPA | 40% Pre-Placement Offers | 670+ Recruiters 
JAGSoM PGDM Admissions 2026
Apply
Highest CTC 51.38 LPA | Median CTC 10.32 LPA | Top 25% Average CTC 14.32 LPA
Great Lakes Institute of Mana...
Apply
Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
Amity University-Noida Law Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity University-Noida MBA Ad...
Apply
Ranked among top 10 B-Schools in India by multiple publications | Top Recruiters-Google, MicKinsey, Amazon, BCG & many more.
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books