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for the following first order ordinary differential equation dy/dt=5y-6t y(0)=-2


pasupulatimareswarao 14th May, 2020
Answer (1)
Rishi Garg 10th Jul, 2020

We are given that  dy/dt = 5y - 6t

rearranging which, we get, dy = 5y.dt - 6t.dt

Integrating both sides, we get

y = 5y.t - 3(t^2) + c

Given, y(0) = -2

which gives,

-2 = 0 + 0 +c

implies C = -2

Hence, the required equation is y = 5y.t - 3(t^2) - 2.

Hope it helps.

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