Hello Aspirant,

Hope you are doing well!!

It is quite difficult to make integration sign, In place of integration sign I'll put |, and in place of power I'll put **  when you are solve in your notebook you can place | sign to integration sign and ** to power

Hello,

This question is very simple. Divide the equation by x. logx, on both sides.

So we get :

dy/dx + y/ x.logx  = 2. logx / x .logx

i.e. dy/dx + y/ x logx = 2/x

Clearly this is a linear differential equation. So firstly we find the integrating

hello aspirant,

you cannot understand differential equations without knowing or having knowledge on total integration.you need to have complete knowledge of both differentiation and integration to understand and solve problems on differential equations.

hope this helps,

thankyou.

Hello sakuntalaampolu,

Well, before I start solving it, I must admit it is going to be very lengthy as I am using bernoulli's homogeneous differential equation method:

Now, In first, if an equation is of form dy/dx = (ax + by + c)/(-bx+ay+f), then we should cross multiply and solve

We are given that  dy/dt = 5y - 6t

rearranging which, we get, dy = 5y.dt - 6t.dt

Integrating both sides, we get

y = 5y.t - 3(t^2) + c

Given, y(0) = -2

which gives,

-2 = 0 + 0 +c

implies C = -2

Hence, the required equation

Hello Aspirant,

I'll recommend you to go through previous year paper for important questions and answers. Also you can purchase few books for sample question papers. These books covers almost all the important area of the subject. Solving these will help you with better understanding and practice.

Good Luck

Hello Prathik,

Hope everything going well.

Here is a method from which you can solve such equation:

Multiplying by 2x/x^2

2(xdx+ydy)+4y(xdy−ydx)/x^2=0

d(x^2+y^2)+4yd(y/x)=0

Converting to polar co ordinates

d(r^2)+4rsinθd(tanθ)=0

2rdr+4rsinθsec^2(θ)dθ=0

2rdr+4rsinθsec^2(θ)dθ=0

dr+2secθtanθdθ=0

Integrating,

r+2secθ=C

√( x^2+y^2)+2 √( 1+tan^2(θ))=C

√( x^2+y^2)+2 √( 1+(y^2/x^2))=C

(x+2) √(x^2+y^2)=Cx

Hope this helps you. Thank you.

All

Hi there!

Greetings!

Hope you are having a nice day!

Here I am giving you that notes of ordinary differential equation of IIT kharagpur :- http://www.math.iitb.ac.in/~siva/afs07.pdf so you can use it any I hope it might help you alot. So keep learning keep practicing and keep growing.

All the best

Hello Nirmal,

(2x+4y-6)dy=(2x-5y +3)dx

This is a very common type of  question that usually comes in the exams . This question is probably from the chapter of Differential Equations. As you understand that it is not that easy to solve the entire question here in the chat box so I

Hey there

Maths and chemistry are scoring. Chemistry has no long writing SA type questions and thus you can score maximum in this subject. Physics has derivations and thus you have to learn stepwise skill to write derivations. Maths is calculative but write neat and clean do not cross too