Hi aspirant,

You have obtained 99.8 percentile in JEE Main. Based on this your Common Rank list (CRL) rank would be 13,000 and the corresponding OBC category rank would be 2,700.

The last year seventh round OBC category closing rank for Computer Science Engineering (CSE) at NIT Rourkela was approximately 4,400 under homestate quota and 1,100 under other state quota. So if you have the home state quota then you will get CSE there.

The last year seventh round OBC category rank for Computer Science Engineering (CSE) at NIT Warangal was approximately 1,100 under homestate quota and 660 under other state quota. So here you would not get Computer science Engineering (CSE). To see you other options you can use our college predictor tool by clicking on the following link: https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor

All the best.

Hello,

For CSE at NIT warangal,you need minimum of 99.5 percentile even considering your category.

For CSE at NIT Rourkela,you need minimum of 99.3 percentile if belonging to other state,if belonging to home state,then you can definitely get CSE at NIT-Rourkela considering obc-home state quota.

You can also use our college predictor tool:

Hope that helps;