Four terms in AP where sum in given are a-3d, a-d , a+d, a+3d.
Hello there!
Greetings!
Although you haven't completed your question, I got your question and providing you its solution below :'-
We have ,
a – 3d + a – d + a + d + a + 3d = 360 o (sum of angles of quadrilateral)
4a = 360 o
a = 90 o
According to question,
(a + d) – (a – d) = 10 o
2d = 10 o
d = 5 o
Therefore, (a – 3d) = 90 o – 15 o = 75 o
(a – d) = 90 o – 5 o = 85 o
(a + d) = 90 o + 5 o = 95 o
(a + 3d) = 90 o + 15 o = 105 o
So ,we got all the angles.
Thankyou