Hello there! 

Greetings! 

Although you haven't completed your question,  I got your question and providing you its solution below :'-

We have ,

a – 3d + a – d + a + d + a + 3d = 360o(sum of angles of quadrilateral)

4a = 360o

a = 90o

According to question,

(a + d) – (a – d) = 10o

2d = 10o

d = 5o

Therefore, (a – 3d) = 90o – 15o = 75o

(a – d) = 90o – 5o = 85o

(a + d) = 90o + 5o = 95o

(a + 3d) = 90o + 15o = 105o

So ,we got all the angles.

Thankyou