Question : From the top of an upright pole $24 \sqrt{3}$ feet high, the angle of elevation of the top of an upright tower was $60^{\circ}$. If the foot of the pole was 60 feet away from the foot of the tower, how tall (in feet) was the tower?

Option 1: $84 \sqrt{3}$

Option 2: $36\sqrt{3}$

Option 3: $44\sqrt{3}$

Option 4: $60\sqrt{3}$

Question : From 40 metres away from the foot of a tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?

Option 1: $\frac{120}{\sqrt{3}}$ m

Option 2: $\frac{60}{{\sqrt3}}$ m

Option 3: $\frac{50}{{\sqrt3}}$ m

Option 4: $\frac{130}{{\sqrt7}}$ m

Question : A 1.6 m tall observer is 45 metres away from a tower. The angle of elevation from his eye to the top of the tower is 30°, then the height of the tower in metres is: (Take$\sqrt{3}=1.732$)

Option 1: 25.98

Option 2: 26.58

Option 3: 27.58

Option 4: 27.98

Question : A person 1.8 metres tall is $30 \sqrt{3}$ metres away from a tower. If the angle of elevation from his eye to the top of the tower is 30°, then what is the height (in m) of the tower?

Option 1: 32.5

Option 2: 37.8

Option 3: 30.5

Option 4: 31.8

Question : At 129 m away from the foot of a cliff on level ground, the angle of elevation of the top of the cliff is 30°. The height of this cliff is:

Option 1: $50\sqrt{3}$ m

Option 2: $45\sqrt{3}$ m

Option 3: $43\sqrt{3}$ m

Option 4: $47\sqrt{3}$ m