Question : G and AD are respectively the centroid and median of the triangle $\triangle$ABC. The ratio AG : AD is equal to:
Option 1: 3 : 2
Option 2: 2 : 3
Option 3: 2 : 1
Option 4: 1 : 2
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Correct Answer: 2 : 3
Solution : The point of intersection of the medians of a triangle is called the centroid. It divides each median in the ratio 2 : 1. So, $\frac{AG}{GD}=\frac{2}{1}$ Let AG = 2 units, GD = 1 unit $\therefore$ AD = AG + GD = 2 + 1 = 3 units Now, $\frac{AG}{AD}=\frac{2}{3}$ $\therefore$ AG : AD = 2 : 3 Hence, the correct answer is 2 : 3.
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Question : $\triangle ABC$ is an equilateral triangle with a side of 12 cm and AD is the median. Find the length of GD if G is the centroid of $\triangle ABC$.
Option 1: $6 \sqrt{3}$ cm
Option 2: $3 \sqrt{3} $ cm
Option 3: $4 \sqrt{3} $ cm
Option 4: $2 \sqrt{3}$ cm
Question : In a $\triangle ABC$, AD, BE and CF are the medians from vertices A, B, and C, respectively. The point of intersection of AD, BE and CF is called
Option 1: median point
Option 2: orthocentre
Option 3: centroid
Option 4: incentre
Question : In $\triangle$ABC, D and E are points on AB and AC, respectively, such that DE || BC and DE divide the $\triangle$ABC into two parts of equal areas. The ratio of AD and BD is:
Option 1: $1:1$
Option 2: $1:(\sqrt2-$1)
Option 3: $1:\sqrt2$
Option 4: $1:(\sqrt2+$1)
Question : If D and E are the mid-points of AB and AC respectively of $\triangle$ABC then the ratio of the areas of $\triangle$ADE and square BCED is:
Option 1: 1 : 2
Option 2: 1 : 4
Option 3: 2 : 3
Option 4: 1 : 3
Question : $\triangle$ABC is similar to $\triangle$PQR and AB : PQ = 2 : 3. AD is the median to the side BC in $\triangle$ABC and PS is the median to the side QR in $\triangle$PQR. What is the value of $(\frac{BD}{QS})^2$?
Option 1: $\frac{3}{5}$
Option 2: $\frac{4}{9}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{4}{7}$
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