2652 Views

heat product in a conductor of resistance 4.2 ohms with 10 amp.current is


ashish aru 24th Apr, 2018
Answers (2)
Vinay krishna 8th Jul, 2021

Here is the exciting solution for your questionguys keep liking.



R= 60 ohm

M= 42kg

I=7 A

Heat produced is

H = RI^2

= 4.2 × 10 ×10

= 420 CAL/SEC

BETO ENJOY WITH THE SOLUTION











Ankita Tibrewal 24th May, 2018

Heat= I*r

4.2*10

42 is the answer

2 Comments
Comments (2)
24th May, 2018
Sorry it's I.I.r
4.2*4.2*10
176.4 is the answer

Am very sorry for the inconveniences.
Reply
Oo
3rd Jul, 2019
Heat = i^2 r Here I = 10A          R= 4.2 ohm        Hence i^2 r = 10×10 (4.2)                               420 joules per second           Which gives 100 calories per second as 1 cal = 4.2 joules
Reply

Related Questions

Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amrita University B.Tech 2026
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Amity University, Noida | Law...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Great Lakes Institute of Mana...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
Manav Rachna University Law A...
Apply
Admissions open for B.A. LL.B. (Hons.), B.B.A. LL.B. (Hons.) and LL.B Program (3 Years) | School of Law, MRU ranked No. 1 in Law Schools of Excelle...
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books