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how to find percentage of s character in c-o bonding


aatifmughal83 23rd Oct, 2020
Answer (1)
gauravvijayvargiya399 24th Oct, 2020

Hello Aspirant,

As per Bent's rule, a more electronegative element decreases the % of s character in the bond or electronegative element occupy the position where s character is less.

Also, lone pair increases the percentage of s character or lone pair occupy the position where s character is more.

Order of S character is given below for each hybridization ,

sp> sp2 > sp3> sp3d

You can also use the formula given below to find out % of s character in hybridized orbitals,

= No. of s orbitals ×100÷ no. of total orbitals

For example, let's consider sp hybridization, and check the % of s character,

~   1×100 ÷2 = 50%

And for sp2 hybridization,

~.    1 ×100÷3= 33.3 %

Hope that helps.

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