The number must be 57. It satisfies both the conditions as well. The digit at tens place that is 5 and the digit and units place ie 7 both are consecutive prime numbers and their sum 5+7 = 12 have 3 and 4 both as its factors. Means 12 is the multiple of both 3 and 4. So 57 must be the answer.
Thank you.
Question : In a two-digit number, its unit digit exceeds its tens digit by 2 and the product of the given number and the sum of its digits is equal to 460. The number is:
Option 1: 48
Option 2: 64
Option 3: 46
Option 4: 36
Question : In a two-digit number, the digit at the unit place is 1 less than twice the digit at the tens place. If the digits at the units place and tens places are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is:
Option 1: $59$
Option 2: $23$
Option 3: $35$
Option 4: $47$
Question : There is a number consisting of two digits, the digit in the unit place is twice that in the tens place and if 2 is subtracted from the sum of the digits, the difference is equal to $\frac{1}{6}$th of the number. The number is:
Option 1: 26
Option 2: 25
Option 3: 24
Option 4: 23
Question : The ratio of a two-digit number and the sum of the digits of that number is 4 : 1. If the digit at the unit's place is 3 more than the digit at the ten's place, then the number is:
Option 1: $47$
Option 2: $69$
Option 3: $36$
Option 4: $25$
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