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i am a obc condidate of haryana state. my persentile in JEE main january is 96.4678. can i get the CSE in NIT Kurukhetra. please tell me and any other NIT which is possible to get a CSE.


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sanjaydahiya1 27th Jul, 2020
Answers (2)
AJAY KUMAR POLAVENI 27th Jul, 2020

dear aspirant!

Your expected rank will be around 30697

the formula to calculate is (100-your total percentile)*869010/100

In 2020 JEE main January session 869010 candidates appeared. Your category rank is expected to be in between 8000-11000. You have not mentioned your state and whether you belong to OBC-NCL or OBC-CL. If you belong to OBC-Cl you will be considered as general category candidate. In 2019 the cut off was follows for NIT, Kurukshetra for admission to CSE

Home state

  • General: 8756
  • OBC-NCL: 4058

Other State

  • General: 6313
  • OBC-NCL: 2718

Considering this you may not get seat irrespective of your category. But cut off may increase or decrease depending on number of candidates appeared, number of seats available and other such factors.

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Please try our JEE main college predictor to know the chances of getting seat in a college

i hope this helps

GOODLUCK!



Divyansh Verma 27th Jul, 2020
Hi dear aspirant , as you mentioned your percentile is around 96.4 so according to this your general rank will lie in between 30k to 31k and your obc rank will lie in between 8000to 10000 . If you belong to obc ncl then your obc rank will be considered but if you belong to obc cl than your general rank will be considered . I would also like to add that the cut off of last year was -
Home state
Obc 2839
General 7265
Based on the earlier cut off you have low chances of getting a seat in cse branch . So i will suggest you to try for other colleges . Hope it will help you . Moreover you can try our
JEE MAINS RANK PREDICTOR .
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