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i am getting 177 in 7 jan shift 2 what will be my percentile


bhikan chavan 16th Jan, 2020
Answers (3)
Vandana Arora 17th Jan, 2020

Hello! The JEE Mains exam which is organized by NTA is national level exam which is now conducted twice a year. So the rank list is based on the highest percentile in either of the attempt. So, you will know your exact rank only after the april attempt is over.

You can calculate your percentile using the formula:

(No. of people having less than 177 marks in second shift/total number of students present in second shift)*100

So your estimate percentile from last year's data will lie between 99.06329703 - 98.85683701 which will get you admission in many colleges across the country. This will vary according to the change in factors like no. of students or the overall difficulty of the paper.

Now, lets calculate your rank. The rank is calculated using the formula-

1+((100-P) * No. of total students appearing)/100)

Your estimate rank will be from 6000 to 9500.

For more accuracy in your rank prediction you can refer to our jee mains rank predictor:

To get even more amazing results in your april attempt you can refer to our JEE Mains pack: https://learn.careers360.com/knockout-jee-main-april/

Hope the answer helps.

sudheer kumar 16th Jan, 2020

dear aspirant,

After considering the Paper 1 inputs

Your Overall Percentile is: 99.34 - 99.54

Your General Rank is: 4107 - 5757.

To know more about rank please visit the given link:

best of luck!

Ritisha Kothari 16th Jan, 2020

Considering you are a general candidate with no disabilities, the prediction of your percentile is as follows:

Your Overall Percentile is: 99.34 - 99.54

Your General Rank is: 4107 - 5757


Also, you can go through the following link to predict your percentile:


Hope this helps!

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