Hello,

It would be difficult to provide you the exact information as JEE Main is being conducted twice by NTA for the first time. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 69,785. With this rank the chances are less to get a seat in NITs, You can also prefer the previous year cutoff to take an Idea about the cutoff.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

If you wish to take the admission in IITs ( IIT Kharagpur & IIT Roorkee) for Architecture programme, You need to appear for JEE Main Paper I after qualifying it you need to appear for JEE Advance AAT. On the basis of JEE Main Paper II score you can not go for IITs.

Good Luck!