Hey Meghana,

According to the formula (100 - your total score) X 112679 /100 your estimated rank is coming out to be AIR 38310 which is a below-average rank for JEE- Main paper 2. Your overall rank can vary as the number of students appearing in the April attempt may increase.

As you know that very few reputed colleges have the course of B.Arch. so you are required to have a high rank to pursue B. Arch. in the colleges mentioned below.

MNIT, Jaipur - 940

MANIT, Bhopal - 1807

NIT, Callicut - 821

NIT Hamirpur -3934

NIT Patna - 4686

NIT Raipur - 3190

NIT Rourkela - 1717

NIT Tiruchirappalli - 1189

VNIT Nagpur -897

The cut-offs are of the general category of 2019 and are taken from the Careers360 website. As you can see, these top-notch colleges demand a very high rank so, try harder for the April attempt to get into your dream colleges. You can also save your year for applying for private colleges and state level colleges.

You may go through the link mentioned below for the JEE Main paper 2 college predictor to get the list of colleges you are eligible with.

Link - JEE Main College Predictor

Good Luck!

Dear Aspirant,

You can calculate your rank by the formula which is given by National Testing agency.the formula is

No of Candidates appeared in session /100 *(100-Nta score ).

So the no of candidates appeared in paper 2 were

112679

So your rank will be 38310

It's quite difficult to get nit at this rank so you should try your best in next Jee main attempt.You devote specefic time to studies and then you can score well.

If you want to predict college according to your percentile scored in exam then you can easily visit the link mentioned below

Thanks

All the very best