Answers (3)
ojaswiyolo Student Expert 30th May, 2019

According to the eligibility criteria the candidate should have secured 75% (GEN) and 65%(OBC SC ST PwD)marks in 12th standard to qualify for the examination as well as JEE Main Counselling (JoSAA) and should have secured above the cutoff rank in JEE MAIN 2019 paper. . The counselling issupposed to start from 2nd week of June, 2019.Since the cutoff. The JEE Main cutoff is the minimumscore JEE aspirants need to secure to be aligible for JEE Advanced. JEE Main Admission cutoff is released by JOSAA for admission to participating institutes. With a score of 45 in JEE Main your percentilewould be around 67and rank around 368564 to 386992.  If you belong to General category you may get admission in Dr. B.C. Roy Engineering College (Durgapur) in EE

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Alok Dixit 30th May, 2019

Hii Aspirant,  Your marks in jee main was not enough to get the admission in the Samrat Ashok Technological institute . But dont loose hope there are so many colleges that you can take it for the B. Tech.

I am providing you a link through which you can predict your college on the basis of your rank.

Https://www.google.co.in/amp/s/engineering.careers360.com/articles/jee-main-rank-predictor/amp

I hope it will help you still if you have any doubt then free to comment.

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Lasya_1491387620 Student Expert 30th May, 2019
Hi Dhawal Dixit, Congrats for the marks you scored in 12th. The cutoff mark for the open category might be above 100 in JEE mains but your marks are 45 for which you cannot get an admission for a open category student.



Here is the link for rank below:

https://www.google.co.in/amp/s/engineering.careers360.com/articles/jee-main-rank-predictor/amp


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