Hello there,
With 91.62 percentile, your All India Rank will be in the range of 84000 to 1lakh approximately. Since you belong to the SC category, your category rank will be in the range of 3000 to 4600 approximately. You haven't mentioned your home state. Analysing the previous year data, you can get some lower NITs.

You can check the cut-off rank of all the NITs from the link given below:
https://www.google.com/amp/s/engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches/amp

Also note that the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.

You can also use our college predictor to predict the best college for you:
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hope this answer helps you.
Good luck!!

Dear student,

Here is a list of the nit's that you could get admission in according to the previous years cut off considering your percentile to be 91.62 and your category to be st:

• NIT Trichy - National Institute of Technology
• NIT Rourkela - National Institute of Technology
• NIT Warangal - National Institute of Technology
• NIT Calicut - National Institute of Technology
• NIT Delhi - National Institute of Technology, Delhi
• NIT Kurukshetra - National Institute of Technology
• MNNIT Allahabad - Motilal Nehru National Institute of Technology
• NIT Durgapur - National Institute of Technology
• MNIT Jaipur - Malaviya National Institute of Technology
• MANIT - Maulana Azad National Institute of Technology
• NIT Patna - National Institute of Technology

At this percentile your all India rank would be around 85,000-90,000 and to know which more colleges you can get at this percentile,  use our rank predictor tool:

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Joint Entrance Examination (Main)

Answer Key | Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Result | Accepting Colleges

Get Updates Brochure