Hello Aryan kartik 

Since this is percentile score it only tells about relative performance of Candidates in their respective session.I can give you rough idea about your rank under general quota using this formula:{100-percentile score}×145386/100.Your rank will be around4.3k.,And you are close of lot NITs.You still have one attempt for jee mains paper 2.This time confirm seat in various NITs.

GOOD LUCK!

Yes you will get seat in nit .

Hello Aryan

Congrats for scoring 97.005 percentile in JEE main paper 2.

We can't say that which NIT you wil get but we can predict the rank with this percentile .

There is a pedicted formula from our team to predict rank

 Total No of students = 145386

Formula

Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100

So your predicted rank  = 4354 approx

Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.

You have  scored very  good percentile so according to me you will get admission  in following NIT's...

• National Institute of Technology, Tiruchirapalli, Tamilnadu
• National Institute of Technology, Warangal, Andhra Pradesh
• National Institute of Technology, Surathkal, Karnataka
• Moulana Azad National Institute of Technology, Bhopal, M.P
• Motilal Nehru National Institute of Technology, Allahabad, U.P
• National Institute of Technology, Calicut, Kozhikode, Kerala
• National Institute of Technology, Durgapur, West Bengal
• National Institute of Technology, Hamirpur, Himachal Pradesh
• Malaviya National Institute of Technology, Jaipur, Rajasthan
• Dr. B R Ambedkar National Institute of Technology, Jalandhar, Punjab

I hope you get my point.

Good Luck!!!