Hi dear,

You have scored 96.2 percentile in JEE main paper 2 that means your rank should be around 4485. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

Last year cutoff of NIT Trichy was

General-home state(opening and closing rank)and other state(opening and closing 4)

1189

2468

121

1075

OBC-NCL

793

1043

338

652

SC

175

271

131

163

ST

366

741

103

103

EWS

652

798

141

158

So if you belong from category then you have some chance otherwise you have to reappear in april month exam and perform better.

Hope it helps