Amritha, you can calculate your approximate rank for JEE Mains using your percentile through the following formula:

(100-your total percentile) x 869010/100

So with 98.93 percentile, your rank would be around 9298.

Also, if the number of students increases to 12 lakh in the April session, the formula for rank calculation would change to:

(100-your total percentile) x 1200000/100

Hence your expected rank in this case would be around 12840.

For IIIT Hyderabad, the cutoff percentile for admission in CSE was 99.958238 after round 1 and 99.9187734 after round 2 of counselling. Now the cutoff tends to vary every year but with 98.93 percentile, it will be difficult to get into IIIT Hyderabad. Although you can get a seat in CSE in NITs like Durgapur, Bhopal, Jamshedpur, Patna and Calicut.

For more details on cutoff for IIIT Hyderabad for different branches in the past years, you can visit: https://engineering.careers360.com/articles/iiit-hyderabad-btech-cutoff/amp

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is:

All the best.