hello.....
3x+2(x+2)=2x+16
3x+2x+4=2x+16
5x+4=2x+16
5x-2x=16-4
3x=12
x=4
answer- B.4
Hello,
Answer is B
4
3x + 2x + 4 = 2x + 16
5x - 2x = 12
3x = 12
x= 4
Hope you understand!
Question : Expand and simplify $(x+4)^2+(x-2)^2$.
Option 1: $2(x^2+2x+10)$
Option 2: $2(x^2+2x-10)$
Option 3: $2(x^2-2x+10)$
Option 4: $2(x^2-2x-10)$
Question : If $3x–3<3+\frac{x}{2}$ and $x–2\leq 6+2x$, then $x$ can take which of the following values?
Option 1: 6
Option 2: 2
Option 3: 10
Option 4: –10
Question : If $\alpha$ and $\beta$ are the roots of equation $x^{2}-x+1=0$, then which equation will have roots $\alpha ^{3}$ and $\beta ^{3}?$
Option 1: $x^{2}+2x+1=0$
Option 2: $x^{2}-2x-1=0$
Option 3: $x^{2}+3x-1=0$
Option 4: $x^{2}-3x+1=0$
Question : If $27 x^3-64 y^3=(A x+B y)\left(C x^2-D y^2+12 x y\right)$, then the value of $4 A+B+3 C+2 D$ is:
Option 1: 5
Option 2: 3
Option 3: –3
Option 4: –4
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile