Hello Aspirant,
See this is very simple aptitude problem, in which every alphabet is given with code of two times of their position like A is 1st alphabet so A=1*2 and likewise B=2*2 and so on, so KNOT can be written as
K = 11*2 = 22
N = 14*2 =28
O = 15*2 = 30
T = 19*2 = 38
Now sum all above values i.e. 22+28+30+38 = 120. SImilarly for DIYA, it will be written as :
D = 4*2 = 8
I = 9*2 = 18
Y = 25*2 = 50
A = 1*2 = 2
So DIYA will be 8+18+50+2 = 78. So code for DIYA is 78.
I hope this information helps you.
Good Luck!!
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