Question : If a + b + c = 0, then the value of (a + b – c)2 + ( b + c – a)2 + ( c + a – b)2 is:
Option 1: 0
Option 2: 8abc
Option 3: 4(a2 + b2 + c2)
Option 4: 4(ab + bc + ca)
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Correct Answer: 4(a2 + b2 + c2)
Solution : a + b + c=0 ⇒ a + b = –c --------------(i) ⇒ b + c = –a --------------(ii) ⇒ c + a = –b --------------(iii) Substituting (i), (ii) and (iii) in (a + b – c)2 + (b + c – a)2 + (c + a – b)2, we get (a + b – c)2 + (b + c – a)2 + (c + a – b)2 = (–c –c)2 + (–a –a)2 + ( –b –b)2 = 4c2 + 4a2 + 4b2 = 4(a2 + b2 + c2) Hence, the correct answer is 4(a2 + b2 + c2).
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Question : If a + b + c = 1, ab + bc + ca = –1, and abc = –1, then what is the value of a3 + b3 + c3?
Option 1: 1
Option 2: 5
Option 3: 3
Option 4: 2
Question : If $a + b + c = 0$ and $ab + bc + ca = -11$, then what is the value of $a^2+b^2+c^2$?
Option 1: –11
Option 2: 22
Option 3: 0
Option 4: 11
Question : If (a + b + c) = 7 and ab + bc + ca = 12, find the value of a2 + b2 + c2.
Option 1: 29
Option 2: 31
Option 3: 27
Option 4: 25
Question : If a + b + c = 15 and a2 + b2 + c2 = 83 then the value of a3 + b3 + c3 – 3abc:
Option 1: 200
Option 2: 180
Option 3: 190
Option 4: 210
Question : For real $a, b, c$ if $a^2+b^2+c^2=ab+bc+ca$, then value of $\frac{a+c}{b}$ is:
Option 2: 2
Option 4: 0
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